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For example, if you were to walk 100 meters north in 50 seconds, your average velocity would be 50 s100 m = 2 m/s north It began the trip at a speed of 0 m/s This shows that average velocity considers both distance and time, reflecting your overall change in position.
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A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds Therefore, the chosen answer is +1.11 m/s. It began the trip at a speed of 0 meters per second
By the time it reached the buoy, it was going 10 meters per second
What was the average velocity of the boat? What was the average velocity of the boat Responses −3.33 m/s2 negative 3.33 meters per second squared −1.11 m/s negative 1.11 meters per second +1.11 m/s plus 1.11 meters per. Solve for speed, distance, time and rate with formulas s=d/t, d=st, d=rt, t=d/s
Calculate rate of speed given distance and time Find mph, miles per hour, km/hour. It began the trip at a speed of o m/s By the time it reached the buoy, it was going 10 m/s
A) 3.33 m/s^2 b) 1.11 m/s c) +1.11 m/s d) +3.33 m/s topic
Physics view solution question 2 views The average velocity of the speedboat is calculated as +1.11 m/s by dividing the total displacement (20 meters) by the total time taken (18 seconds)
